> I think we're wasting time here. > > At the binary level, both: > Displacement const disp; > and > Displacement disp; > are identical.
And, with any sane compiler so is:
Displacement const disp = Displacement(); auto const disp = Displacement(); auto const& disp = Displacement();
etc.
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> I think we're wasting time here.
>
> At the binary level, both:
> Displacement const disp;
> and
> Displacement disp;
> are identical.
And, with any sane compiler so is:
Displacement const disp = Displacement();
auto const disp = Displacement();
auto const& disp = Displacement();
etc.